While differential calculus is about finding rates of change (slopes), integral calculus is about accumulating quantities, most often visualized as finding the area under a curve.
The indefinite integral of a function f(x), denoted ∫f(x)dx, asks the question: 'What function, when differentiated, gives me f(x)?' For this reason, it is also called the antiderivative.
The Reverse Power Rule:
Just as we have a power rule for derivatives, we have one for integrals.
To find the integral of xⁿ:
∫xⁿ dx = (xⁿ⁺¹) / (n+1) + C
In words: add one to the exponent, then divide by the new exponent.
The Constant of Integration, C:
Notice the '+ C'. When we differentiate a constant, it becomes zero. This means there are infinitely many functions that have the same derivative (e.g., the derivatives of x² + 2, x² - 10, and x² are all 2x). The '+ C' represents this unknown constant and must always be included in an indefinite integral.
Example: Find ∫4x³ dx.
The definite integral, denoted with limits of integration, calculates the net area between the function's graph and the x-axis over a specific interval [a, b].
∫ₐᵇ f(x)dx
This value is a number, not a function. Areas above the x-axis are positive, and areas below are negative.
This is one of the most important theorems in all of mathematics because it provides the bridge connecting differential and integral calculus. It states that we can evaluate a definite integral by using the antiderivative.
If F(x) is an antiderivative of f(x), then:
∫ₐᵇ f(x)dx = F(b) - F(a)
In words: to find the area under f(x) from a to b, find the antiderivative F(x), evaluate it at b and a, and subtract the results. This is a much easier method than the original technique of summing up an infinite number of tiny rectangles (Riemann sums).
Example: Find the area under the curve f(x) = 2x from x=1 to x=3.
What is the indefinite integral of the function f(x) = 6x² + 5?
What does the definite integral ∫ₐᵇ f(x)dx represent geometrically?
Use the Fundamental Theorem of Calculus to evaluate the definite integral of f(x) = 3x² from x = 0 to x = 2.